Rohit Sharma's second consecutive fifty, Mumbai defeated Hyderabad by 7 wickets in his house
News Update April 24, 2025 06:24 AM

SRH vs MI IPL 2025: Mumbai Indians won the 41st match of the Indian Premier League 2025 by 7 wickets. Hyderabad suffered a big defeat against MI in his house. This was MI's fourth consecutive win. At the same time, SRH had a sixth defeat in the 8th match. Rohit Sharma played an important role in MI's victory who scored his second consecutive half -century. Please tell that MI had to score 144 runs to win.

Rohit Sharma's second consecutive fifty

For the Mumbai Indians, Rohit Sharma once again bowled well and scored a second consecutive half-century. This was the first time since 2016 when Rohit has put a fifty in back-to-back matches. Rohit, who scored an unbeaten 76 in the last match, scored 3 sixes and 8 fours in this match, scoring 70 runs. Apart from this, Suryakumar Yadav scored an unbeaten 40 in 19 balls. MI won the match by scoring 146 runs for 3 wickets in 15.4 overs. With this victory, MI has gone to number three in the points table.

SRH could score just 143 runs

Sunrisers Hyderabad came to bat first after losing the toss. The team was very poor and lost 5 wickets at 3,5, but with the help of Henrik Klassen's 71 and Abhinav Manohar's 43 runs, SRH could reach 143 for 8 wickets. This was Klassen's half-century in IPL 2025.

Bolt and Deepak Chahar's deadly bowling

Trent Bolt and Deepak Chahar played an important role in stopping the stormy batsmen of SRH at 143. Bolt took 4 wickets for 26 runs in 4 overs, while Deepak took 2 wickets for 12 runs in 4 overs. Jaspreet Bumrah and Hardik Pandya got 1-1 wickets.

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