UPPSC Normalization Formula: Uttar Pradesh Public Service Commission (UPPSC) has announced the dates of PCS Preliminary Examination (UPPSC PCS) and Review Officer-Assistant Review Officer Preliminary Examination (UPPSC RO ARO). Both the recruitment examinations will be conducted in December 2024. Both examinations will be conducted in more than one shift. In such a situation, the commission has announced that the normalization formula will be used for evaluation in these recruitment examinations.
The commission has also told how the percentage score of the candidates will be calculated. The formula to be used for this has also been published. The formula is also explained below in the news.
UPPSC PCS Prelims Exam Date 2024: Date of PCS Preliminary Examination
According to the schedule released by the commission, these recruitment examinations will be conducted in December 2024. UPPSC PCS Preliminary Examination will be held on 7th and 8th December in 41 districts of the state. The exam will be conducted in two sessions, in which the first session exam will start from 9.30 am to 11.30 am and the second session exam will start from 2.30 pm.
UPPSC RO ARO Exam Dates: RO-ARO exam will be held on 22, 23 December
RO-ARO preliminary exam will be conducted on 22 and 23 December. The exam will be conducted in a total of three shifts on both days. The third shift exam will be conducted on 23 December. On December 22, the first shift will be from 09:00 am to 12:00 pm, the second shift will be from 02:30 pm to 05:30 pm and the third shift will be from 09:00 to 12:00 pm on December 23.
The normalization formula also released
Along with releasing the exam dates, the commission has also released the evaluation formula for the preliminary examination to be held in more than one shift. The Commission has said that the committee of experts had recommended the above formula after a thorough study of the court orders.
What is the normalization formula?
According to this formula, to know the percentage score of a candidate, the quotient of the number of all candidates securing marks equal to or less than the marks secured by him and the total number of candidates present in that shift has to be multiplied by 100.
For better understanding, suppose a candidate of j shift scored X marks. A total of N candidates appeared for the exam in this shift. Then to know the percentage score of that candidate, first the total number of candidates securing marks equal to or less than X has to be divided by N, i.e. the total number of candidates present in that shift. Now by multiplying the quotient by 100, the percentage score of the candidate will be obtained.
The Commission has said that the percentage score of the candidates can be up to six digits after decimal (00.000000%).